Automated Pure Water 400 Manuale di installazione e funzionamento - Pagina 4

Sfoglia online o scarica il pdf Manuale di installazione e funzionamento per Sistemi di filtrazione dell'acqua Automated Pure Water 400. Automated Pure Water 400 8. Non-electric dry chlorine pellet feeder

Stampa la pagina

Theory of Operation

After filling the unit with chemical to no higher than the

bottom of the adjustable cap or less and returning water

flow, fluid will flow into the chemical container mixing with

the chemical until the air trapped in the top of the unit is

compressed to the same pressure as the line pressure.

When the line pressure is reduced, compressed air in the

air chamber will force fluid from the container down and

up through the outside center tube and down the inside

tube to the water line until pressure is equal or until the

fluid level reaches the hole that is open in the outside

tube. At that time the compressed air will flow through

the hole into the outside tube, down the inside tube and

no more fluid will flow. This procedure will occur on each

pump cycle. The outside tube has six (6) holes with three

of them smaller. The cap can be rotated to select either a

Approximate Chlorine Concentration Per Pump Cycle

To oxidize one PPM of Hydrogen Sulfide (H

PPM of Chlorine (Cl

). To oxidize 1 PPM of Iron (Fe) it takes

.64 PPM of Cl

Example: If you have 4 PPM of Fe and 1 PPM of H

on the vertical portion of the graph labeled PPM

and start at 4 and move horizontal to the line

marked Iron - Fe X . 64 Cl

bottom of the graph marked Chlorine - Cl

It should intercept the bottom about 2. 6. This

is the amount of Cl2 needed to oxidize 4 PPM of

Fe. Now look on the vertical portion of the graph

labeled PPM and start at 1 and move horizontal

to the line marked Hydrogen Sulfide - H

and then down to the bottom of the graph.

It should intercept the bottom about 2.2. This

is the amount of Cl

of H

Example in dotted lines:

4 PPM Fe requires 2.6 PPM of Cl

1 PPM H

S requires 2.2 PPM of Cl

Total Cl

required is 2.6 plus 2.2 = 4.8 PPM Cl

Model 400 Non-Electric Dry Chlorine Pellet Feeder

S), it takes 2.2

S, look

and then down to the

PPM.

S X 2.2

needed to oxidize 1 PPM

large hole or a small hole in six different locations. During

fluid flow a small amount of fluid will flow through the hole

selected thereby diluting the fluid flowing up through the

outside tube. Most chemical solutions are heavier than

water and the top of the fluid is not as heavily saturated

as the bottom of the container. Selecting a small hole will

increase the chemical concentration and selecting a lower

hole increases the solution output.

The unit can be used as a venturi operation for operations

other than varying pressure. In this mode the cap may

be rotated so there is no hole through the outside tube or

left with the hole through the outside tube to help dilute

the fluid if needed. The chemical solution out is controlled

with the optional rate of feed valve in a constant pressure

system.

If using a 42 gallon pressure tank, the No. 2 hole on the

Model 400 feeder should be used. This will dispense

about 8 PPM of Cl

carbon after the unit will eliminate the excess Cl

the Model 400 feeder for iron removal or extremely high

S, it is necessary to use a back washing valve on the

carbon filter.

Higher PPM than the graph can be calculated.

Example:

20 PPM H

20 PPM Fe X .64 C~ = 12.8 PPM of Cl

The Model 400 feeder will hold about 4 pounds of Cl

(10 gram tablets). If it is adjusted to the No. 1 hole, and

using a 42 gallon pressure tank with one cube of activated

carbon the system should process approximately 20,000

gallons of water before the unit would need refilling.

-2-

and a filter with one cube of activated

S X 2.2 Cl

= 44 PPM of Cl

. If using