3B SCIENTIFIC PHYSICS 1002956 Istruzioni per l'uso - Pagina 4

Sfoglia online o scarica il pdf Istruzioni per l'uso per Prodotti per l'educazione scientifica 3B SCIENTIFIC PHYSICS 1002956. 3B SCIENTIFIC PHYSICS 1002956 5. Torsion pendulum according to prof. pohl

5. Example experiments
5.1 Free damped rotary oscillations
• To determine the logarithmic decrement Λ, the
amplitudes are measured and averaged out over
several runs. To do this the left and right deflec-
tions of the torsional pendulum are read off the
scale in two sequences of measurements.
• The starting point of the pendulum body is located
at +15 or –15 on the scale. Take the readings for
five deflections.
• From the ratio of the amplitudes we obtain Λ us-
ing the following equation
ϕ
n
Λ =
In
ϕ
n+1
ϕ
n
0 –15
–15
–15
–15
1 –14.8 –14.8 –14.8 –14.8 14.8 14.8 14.8 14.8
2 –14.4 –14.6 –14.4 –14.6 14.4 14.4 14.6 14.4
3 –14.2 –14.4 –14.0 –14.2 14.0 14.2 14.2 14.0
4 –13.8 –14.0 –13.6 –14.0 13.8 13.8 14.0 13.8
5 –13.6 –13.8 –13.4 –13.6 13.4 13.4 13.6 13.6
ϕ
n
Ø
Ø
0
–15
15
1
–14.8
14.8
2
–14.5
14.5
3
–14.2
14.1
4
–13.8
13.8
5
–13.6
13.5
• The average value for Λ comes to Λ = 0.0202.
• For the pendulum oscillation period T the follow-
ing is true: t = n · T. To measure this, record the
time for 10 oscillations using a stop watch and cal-
culate T.
T = 1.9 s
• From these values the damping constant δ can be
determined from δ = Λ / T.
δ = 0.0106 s
–1
• For the natural frequency ω the following holds
true
2
π
2
ω
=
 −
δ
2
T
ω = 3.307 Hz
5.2 Free damped rotary oscillations
• To determine the damping constant δ as a func-
tion of the current Ι flowing through the electro-
magnets the same experiment is conducted with
an eddy current brake connected at currents of
Ι = 0.2 A, 0.4 A and 0.6 A.
ϕ
+
15
15
15
15
ϕ
Λ –
Λ +
+
0.013
0.013
0.02
0.02
0.021
0.028
0.028
0.022
0.015
0.022
Ι Ι Ι Ι Ι = 0.2 A
ϕ
n
0 –15
–15
–15
1 –13.6 –13.8 –13.8 –13.6 –13.7
2 –12.6 –12.8 –12.6 –12.4 –12.6
3 –11.4 –11.8 –11.6 –11.4 –11.5
4 –10.4 –10.6 –10.4 –10.4 –10.5
5
9.2
–9.6
• For T = 1.9 s and the average value of Λ = 0.1006
we obtain the damping constant: δ = 0.053 s
Ι Ι Ι Ι Ι = 0.4 A
ϕ
n
0
–15
–15
–15
1
–11.8 –11.8
–11.6 –11.6
2
–9.2
–9.0
3
–7.2
–7.2
4
–5.8
–5.6
5
–4.2
–4.2
• For T = 1.9 s and an average value of Λ = 0.257 we
obtain the damping constant: δ = 0.135 s
Ι Ι Ι Ι Ι = 0.6 A
ϕ
n
0
–15
–15
–15
1
–9.2
–9.4
2
–5.4
–5.2
3
–3.2
–3.2
4
–1.6
–1.8
5
–0.8
–0.8
• For T = 1.9 s and an average value of Λ = 0.5858
we obtain the damping constant: δ = 0.308 s
5.3 Forced rotary oscillation
• Take a reading of the maximum deflection of the
pendulum body to determine the oscillation am-
plitude as a function of the exciter frequency or
the supply voltage.
T = 1.9 s
Motor voltage V
3
4
5
6
7
7.6
8
9
10
9
ϕ
Λ –
Ø
–15
–15
0.0906
0.13
0.0913
0.0909
–9.6
–9.6
–9.5
0.1
ϕ
Λ –
Ø
–15
–15
–11.7
0.248
–9.0
–9.2
–9.1
0.25
–7.0
–7.0
–7.1
0.248
–5.4
–5.2
–5.5
0.25
–4.0
–4.0
–4.1
0.29
–1
ϕ
Λ –
Ø
–15
–15
–9.2
–9.2
–9.3
0.478
–5.6
–5.8
–5.5
0.525
–3.2
–3.4
–3.3
0.51
–1.8
–1.8
–1.8
0.606
–0.8
–0.8
–0.8
0.81
ϕ
0.8
1.1
1.2
1.6
3.3
20.0
16.8
1.6
1.1
–1
–1