Camille Bauer Sineax p 530 Manuale di istruzioni per il funzionamento - Pagina 19

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Camille Bauer Sineax p 530 Manuale di istruzioni per il funzionamento
Zero
P231
15
16
17 18
+
–
1
2
3
4
5
6
Insert U = U
if U
is not within one of the standard nominal
N
N
voltage ranges.
Insert U =U
if U
is within one of the standard nominal
N min
N
voltage ranges.
Examples for three-wire, three-phase,
asymmetrically loaded schemes
Active power measuring
Example 1:
Change of input voltage from 100 V to 110 V
120 000 V
250 A
, I =
U
=
100 V
5 A
a
132 000 V
250 A
, I =
U
=
110 V
5 A
n
U
110 V
N
· c
=
Ucal =
U
n
100 V
N min
Ucal = 1.1547 V new calibration voltage
Example 2:
Change of c.t. rating from 250 A to 300 A
132 000 V
250 A
, I =
U
=
110 V
5 A
a
132 000 V
300 A
, I =
U
=
110 V
5 A
n
U
110 V
N
· c
=
Ucal =
U
n
100 V
N min
Ucal = 0.9622 V new calibration voltage
U
= new input voltage
n
U
= old input voltage
a
Ucal
Full-scale
–
+
P171
X174 X173
7
8
9
10
11
12
13
14
, 0...60 MW, c
= 1.1547
a
, 0...60 MW, c
= 1.04972
n
· 1.04972
, 0...60 MW, c
= 1.04972
a
, 0...60 MW, c
= 0.87477
n
· 0.87477
Example 3:
Change measuring range from ± 4000 W to ± 3000 W
U
= 400 V, I = 5 A, 4000...0...4000 W, c
N
U
= 400 V, I = 5 A, 3000...0...3000 W, c
N
U
400 V
N
· c
=
Ucal =
U
n
380 V
N min
Ucal = 0.9116 V new calibration voltage
Reactive power measuring
Example 4:
Change of input voltage from 100 V to 110 V
120 000 V
250 A
, I=
U
=
100 V
5 A
a
132 000 V
250 A
, I =
U
=
110 V
5 A
n
U
c
·
N
n
Ucal =
U
0,7
N min
Ukal = 0.9997 V new calibration voltage
Example 5:
Change of c.t. rating from 250 A to 300 A
132 000 V
250 A
, I =
U
=
110 V
5 A
a
132 000 V
300 A
, I =
U
=
110 V
5 A
n
U
c
·
N
n
Ukal =
U
0.7
N min
Ukal = 0.9164 V new calibration voltage
Example 6:
Change measuring range from ± 2500 Var to ± 2000 Var
U
= 400 V, I = 5 A, 2500...0...2500 Var, c
N
U
= 400 V, I = 5 A, 2000...0...2000 Var, c
N
U
c
·
N
n
Ucal =
U
0.7
N min
Ucal = 0.8682 V new calibration voltage
c
= new calibration factor
n
c
= old calibration factor
a
= 1.15470
a
= 0.8660
n
· 0.866
, 0...40 MVar c
= 0.7698
a
, 0...40 MVar c
= 0.6998
n
110 V
0.6998
=
·
100 V
0.7
, 0...40 MVar c
= 0.6998
a
, 0...40 MVar c
= 0.58318
n
110 V
0.58318
=
·
100 V
0.7
= 0.72168
a
= 0.57735
n
400 V
0.57735
=
·
380 V
0.7
19