DeZurik D10350 Краткое руководство по эксплуатации - Страница 6
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DeZURIK
Position Transmitter
The position transmitter provides a 4 to 20 mA output signal with the plus and minus terminals
connected in series with an external 24 VDC power supply. Voltage variations from 10 VDC to 40 VDC
do not affect the current signal. The maximum load is 700 ohms at 24 VDC. The unit is calibrated as
shown in the following steps. Refer to Figure 3 for component identification.
1. Plug the 3-pin potentiometer connector into the appropriate 3 pins on the 5-pin block as
described in Figure 3. The 5-pin block is located next to the span adjustment.
2. Place the valve in the position desired for 4 mA output. Do not connect power until step 4. If the
valve is in the closed or clockwise position, connect an ohmmeter to terminals 2 and 3 of the
potentiometer; if the valve is in the open or counterclockwise position, connect an ohmmeter to
terminals 1 and 2 of the potentiometer.
3. Loosen the coupling that drives the potentiometer shaft, and rotate the potentiometer so that the
ohmmeter reads 500 ± 100 ohms. Then tighten the coupling, and disconnect the ohmmeter from
the potentiometer.
4. Connect a 20 mA ammeter and a 24 VDC power supply to terminals + and – as shown in Figure
3.
5. Adjust the zero trimpot so that the ammeter reads 4 ± 0.1 mA.
6. Place the valve in the position desired for 20 mA output. Adjust the span trimpot so that the
ammeter reads 20 ± 0.1 mA. The zero and span adjustments are not interactive.
D10350
Figure 3—Position Transmitter
Page 6
May 2014