AIMS Power PWRIX120012SUL Kullanım Kılavuzu - Sayfa 5
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Sayfayı YazdırD. INSTALLATION
Ensure there is enough space for the installation, and the location should be meet
the following requirements:
1. Water should not access the inverter.
2. The ambient temperature should be 32~104°F, and the preferred temperature is
50-77°F. The lower the better in this range of ambient temperature.
3. Allow for 12 inches around the inverter for adequate air flow.
4. Do not mount the inverter upside down.
5. We recommend mounting the inverter on something stable to prevent it from
bouncing. Impact shock could result in damage to your unit. Be sure to use all
four mounting screws for optimal stability. Mount in a location that can support
the weight of the inverter.
6. Allow 12 inches of space around the inverter to prevent objects from blocking the
vents and to provide enough air to circulate.
7. Do not install the inverter in an environment with high dust, saw dust residue or
other particles that may get sucked into the inverter increasing internal
temperature.
8. There will be some electrical arcing or spark when the inverter connects with the
battery. Combustible materials such as gasoline, alcohol, etc. should not be
around the inverter.
E. BATTERY
1. The battery is designed to supply the inverter with DC input voltage and the rated
voltage should be in accordance with the rated input voltage of the inverter. Any
voltage exceeding the range of the input voltage of the inverter will cause the
inverter to go into overload and could possibly damage the inverter. The battery
should supply enough current for the load. The load is the amp or watt rating of
the equipment being powered by the inverter. A small capacity battery cannot
provide enough power for a large electrical equipment. In this case, the battery
will cause the inverter to go into under voltage protection because of the load put
on the battery. A simple way to calculate the load or amps required from your
battery is to divide watts of equipment by battery voltage. Due to the consumption
of the inverter itself, the actual current will be about 10%. For example, the
voltage of lead acid battery is 12VDC, and load of the equipment is 1000W,
therefore, the actual current needed from the battery is about 1000W / 12V = 83.3
amps per hour. Add 10% for efficiency loss and you get 83.3 * 1.10% = 91.6 amp
per hour needed. If you don't know the wattage of your equipment, you can figure
the wattage by multiplying AC amps by AC voltage. For example, a refrigerator is
8 AC amps * 120 Volts AC = 960 watts. Remember, all equipment has a start-up